How much boost will get you 280 at the rear wheels?
#11
Originally posted by derryck
That's okay... I still have your exhaust in my garage.
That's okay... I still have your exhaust in my garage.
#12
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Originally posted by ChrisD
... And that the power gain per air+fuel isn't necessarily linear. Technically that would make a 2 bar (28psi) F20C a 720 HP at the crank monster, ~650? at the wheels? Yikes.
I only say this because I'm a few weeks away from 2 bar and I doubt I'll be hitting 650 at the wheels.
... And that the power gain per air+fuel isn't necessarily linear. Technically that would make a 2 bar (28psi) F20C a 720 HP at the crank monster, ~650? at the wheels? Yikes.
I only say this because I'm a few weeks away from 2 bar and I doubt I'll be hitting 650 at the wheels.
You got the 720 crank hp part right, but not the resulting (if perfect) wheel hp...for a 17% tranny loss, that equates to 598 wheel hp, not 650 hp. Rarely are things linear, but you should still be reasonably close. Is this 2 bar right into the TB, or 2 bar between the compressor and intercooler? If it's between the two, expect some PSI loss there, so you can't calculate the hp gain with a value of 2 bar.
Incidentally, what kind of losses are you guys seeing with the ICs? 10-15%?
#13
[QUOTE]Originally posted by MacGyver
[B]
You got the 720 crank hp part right, but not the resulting (if perfect) wheel hp...for a 17% tranny loss, that equates to 598 wheel hp, not 650 hp.
[B]
You got the 720 crank hp part right, but not the resulting (if perfect) wheel hp...for a 17% tranny loss, that equates to 598 wheel hp, not 650 hp.
#14
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Its all about volumetric efficiency. How the turbo system was designed, manifold flow, I/C efficiency and pressure drop and the size of the turbine, turbine housing, compressor and compressor housing. The more cfm a turbo can flow at a given (constant) psi the more power.....like I stated before not how much boost you are eunning but the efficiency of the system In regards to cooler air being more efficient....I am unsure of this. Like you stated the air is denser thus needing more fuel and creating more power. But from an engineers point of view or explanation, I cannot help you there.......anyone care to chime in
#15
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20 psi is 1.36 bar, not 2.0 if that's what you were referring to. At 20 psi, that's the equivalent of 566 crank hp. Roll that through 17% tranny losses and you're at 470 wheel hp, pretty darn close to that 450 wheel hp you quoted. I'm willing to let a few hp go here and there due to tuning and additional losses at greater torque (increased friction as spinning components are twisted closer to their oiled sidewalls, etc.). From that standpoint, I'd say the numbers you're seeing match up pretty well.
In a nutshell, per psi, one should expect roughly 16 crank hp and 13-14 wheel hp.
Losses certainly aren't restricted to the IC when going FI, but you can expect the majority of your pressure loss through it. At a 10-15% loss, that equates to 2-3 psi when running the compressor at 20 psi. If you're assuming the compressor is at 20 psi and expect to get the 477 whp figure mentioned above, you'll fall short a good 30-40 whp due to IC losses.
In a nutshell, per psi, one should expect roughly 16 crank hp and 13-14 wheel hp.
Losses certainly aren't restricted to the IC when going FI, but you can expect the majority of your pressure loss through it. At a 10-15% loss, that equates to 2-3 psi when running the compressor at 20 psi. If you're assuming the compressor is at 20 psi and expect to get the 477 whp figure mentioned above, you'll fall short a good 30-40 whp due to IC losses.
#16
Registered User
Terry, I would probably say the reverse of your statement is the correct way to say it...the more psi a compressor can push at a particular flow rate (cfm) the more power that's available. For a particular rpm, the engine will need a set amount of air (cfm)...the trick to more power is making that volume of air more dense by raising the psi.
chris, It's difficult to answer your question about efficiency without understanding your definition of efficiency in this context. As you stated, a cooler air charge (i.e., more dense) will obviously hold more power potential. One could argue that the hotter charge would affect the bearings and make them slower due to increased friction, one could argue it heats up the engine with the same effect, one could argue all kinds of things, but I'm not so sure it would be useful here. Cool the charge as much as humanly possible before it hits the cylinders and you'll have done the best you can do.
chris, It's difficult to answer your question about efficiency without understanding your definition of efficiency in this context. As you stated, a cooler air charge (i.e., more dense) will obviously hold more power potential. One could argue that the hotter charge would affect the bearings and make them slower due to increased friction, one could argue it heats up the engine with the same effect, one could argue all kinds of things, but I'm not so sure it would be useful here. Cool the charge as much as humanly possible before it hits the cylinders and you'll have done the best you can do.
#17
You guys are calculating your losses due to the drivetrain incorrectly. Tranny losses do not depend on the amount of horsepower your engine developes. It requires a certain amount of power to drive your transmission, which is about 40 horse power for the s2000. So, if you make 300 or 400 horse power it will still take the same amount of power to drive your drivetrain. With that said you will need about 320 hp at the crank for your 280whp.
#18
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The only problem is that we've been seeing closer to 450 rwhp with 20psi
#20
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I think that it all would depend on what kind of supercharger or turbo charger you have on the car. Some are bigger and they can put up with more boost than others.
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