Honda-S2000VTec

How do you calculate engine displacement in liters, bore x stroke x? The total area of a cylinder x 4 then converted into liters?

fltsfshr

i believe you got it

fltsfshr

Elistan

Hmm... F22C1, bore = 87.0mm, stroke = 90.7mm.

Cyl volume = pi*(1/2 * 87)^2 * 90.7 = 539181.9 mm^3 = 539.1819 lcc

539.1819 * 4 = 2156.72 cc.

Therefore to get total engine displacemet:
PI * (half bore)^2 * stroke * 4.

Windscreen

That should be *4 not *8.

For total engine displacement, I use this:

(pi * bore^2 / 4 * stroke) * #cylinders = Vs

pi = 3.14159
bore in centimeters (cm, divide mm by 10 for cm)
stroke in cm
Vs (V sub s) = engine swept volume in cc
the first term in (xx) is the displacement of 1 cylinder

So, for the F20c:

(pi * 8.7^2 / 4 * 8.4) * 4 = 1997 cc (499.35 cc per cylinder)

Steve

Elistan

Indeed. I don't know where that extra doubling came in.

Windscreen

Hey! No fair editing! Now I look like I don't know what the hell I'm talking about.


Steve

Elistan

Hey, don't want to give anybody incorrect information!

SAIYAJIN

how much could the F20C be bored? (assuming you sleeved it)

Honda-S2000VTec

I have done the math for a F20C motor bored out to the max (90mm with Darton sleeves) and a 04 crank (90.7mm stroke) is 2308 cc or 13.47% more displacement.
3.14159*9.0^2/4*9.07*4=2308 cc
Now what happens if I apply 1-Bar of pressure or 14.5-Psi? How could I mathematically factor that in?
If our current atmosphere is 1-Bar and we add 1-Bar more pressure would the volume of air double?

cjb80

If you add 30 psi, you still have the same displacement. "There's no replacment for displacement" ..



Chris