NFRs2000NYC

Ok guys...Im sending in my Audiobahn to get replaced due to a faulty LPF, so in the meantime, I got my friend's Rubicon 302.

Now...its a 2 channel amp....

there are 4 speaker inputs, however, one of the speaker wire screw/holding thingies is missing...So I have NO choice but to bridge the amp.

I am Running an Alpine Type R DVC (2ohm+2ohm) sub.

The amp is rated at:

4ohm stereo : 75w x 2
8ohm bridged: 150 x 1

2ohm stereo: 150 x 2
4ohm bridged: 300 x 1

1ohm stereo 150 x 2
2ohm bridged 300 x 1

So I assume I have to use the 4th option...4ohm bridged...correct??

If so, please tell me how to wire this up.

Is it....

+ of right channel and - of the left channel.... (thats what the amp says is bridged)

so the positive goes to one coil +
negative goes to the OTHER coil -

But now what? Do i connect the other two remaining terminals on the sub together???

Thanks boys!

NFRs2000NYC

Ok...I think I have figured it out, jest let me know if Im right.

For a 2ohm load....

+ to coil a....then + from coil a to + on coil b.

- to coil b....then - from coil b to - on coil a.

Correct?

Jeez im dumb.

NFRs2000NYC

Am I correct junkies?

PJK3

umm...

you can't actually get a 2 ohm load out of a 2 ohm DVC.

what you've described is a 1 ohm load. (parallel)

you'll have to run this sub at a 4 ohm load (series) and get 300 Wrms x 1.

it would have to be:
amp r+ > a +
a - > b +
b - > amp l-


here's a pic that should help: http://www.jlaudio.com/tutorials/wiring/in...ndex.html#1dvcs


remember -
when wiring in series, you add resistances. Rtotal = R1 + R2 + R3 + R....

when wiring in parallel, you've got to do the fractions:
1/Rtotal = 1/R1 + 1/R2 + 1/R3 +...

so, in this case in parallel: 1/Rtotal = 1/2 + 1/2 = 2/2. the inverse of 2/2 = 2/2 = 1 ohm.
but you're not stable @ 1 ohm.

so, in series: Rtotal = 2 + 2 = 4 ohm. which is stable.


now -- if you had a 4 ohm DVC... parallel would be a good option:
1/Rtotal = 1/4 + 1/4 = 1/2 since, this is 1/Rtotal, we need the inverse inverse of 1/2 to get Rtotal. the inverse of 1/2 is 2, so Rtotal = a 2 ohm load.