To be more precise, would the odds of last week's winning #s appear be the same as any random new # winning this week's? I gotta know, I gotta get S2000Qtee that Tiff Ring

 

The events are unrelated.

If your odds of winning are 1 in 1,000,000; the odds of the same numbers repeating the following week are still 1 in 1,000,000.

 

but if the same #'s appear, you should think rigged machine.

 

also, Ev, the M3's value is worth more than the Tiff ring.

 

but wouldn't it be harder to get the exact same numbers twice.
something like
1 in 1,000,000 then
1 in 1,000,000 again
so it'd be 1 in 1,000,000,000,000

both are impossible so i don't know.

 

No, that's only true of related events George. Simple example:

Flip a two-sided fair coin; your odds of getting a head is 1 in 2. Flip the same coin again, and the odds are still 1 in 2. You can extrapolate it to any fair die, or randomly selected numbers from a single pool. The odds of a specific combination repeating are squared as you point. In other words getting two heads in two flips is 1 in 4, getting snake eyes is 1 in 36, getting 1-5-32-44-47 two weeks in a row would be 1 in 1,000,000,000,000 (assuming it was 1 in 1,000,000 the first time). But any arbitrary combo repeating itself is the base odds.

 

WSB is right.... OTOH yes George the odds of getting a number twice in a row are far more remote. That's BEFORE either draw. However since last weeks numbers are what they are the odds are 100%.

I.e. It's 1 in 1 times 1 in 1,000,000 equals 1 in 1,000,000. Make sense?

 

Whoops... WSB already answered

 

yes. so the 1 in 1,000,000,000,000 is if i guess the numbers before the first lotto win?

 

you won't get the ring before i do